Power Electronics & Drives Test - 5 - PDF Flipbook

Power Electronics & Drives Test - 5

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Test-05Solutions


POWER ELECTRONICS & DRIVES
1. Turn-on time of an SCR can be reduced by using a

a) rectangular pulse of high amplitude and wide-width
b) rectangular pulse of low amplitude and hide-width
c) triangular pulse
d) trapezoidal pulse
Answer: (a)
2. The cycle converters require natural or commutation as under
a) natural commutation in both step-up and step-down

cycloconverter
b) forced commutation in both step-up and step-down

cycloconverter
c) forced commutation in step-up cyclo converters
d) forced commutation in step-down cycloconverter
Answer: (c)
3. A compared to oscillators, inverters provides
a) distortion less output
b) highly stabilized output
c) high frequency output
d) low frequency output
Answer: (d)
4. A chopper circuit is operating on TRC principle at a frequency
of 2 kHz on a 220 V dc supply. If the load voltage is 170 V, the
conduction and blocking period of the thyristor in each cycle
are, respectively

1


a) 3.86 μs and 1.14 μs

b) 38.6 ms and 11.4 ms

c) 3.86 ms and 1.14 ms

d) 0.386 ms and 0.114 ms

Answer: (d)

Solution:

For step-down chopper is operating on Time Ratio Control

(TRC) principle, 0 = = ∙


Given, chopping period,

= 1 = 1 = 0.5
2×103

Vs = 220V and V0 = 170V

Now, 170 = (220)( )
0.5×10−3

(0.5 × 10−3) �2127� =

= 0.386

= − = 0.5 − 0.386

= 0.114

5. A 3-phase voltage source Inverter is operated in 1800 conduction

mode. Which one of the following statements is true?

a) Both pole-voltage and line- voltage will have 3rd harmonic

components

b) Pole-voltage will have 3rd harmonic component but line-

voltage will be free from 3rd harmonic

c) Line-voltage will have 3rd harmonic component but pole-

voltage will be free from 3rd harmonic

2


d) Both pole-voltage and line-voltage will be free from 3rd

harmonic components

Answer: (b)

Solution:

= ∑∞ =1,3,5 4 cos sin � + 6 �
6

For triplent harmonic cos 3 = cos = 0
6 2

All triplen harmonic are absent from the line voltages.

Similarly,

Pole voltage = ∑∞ =1,3,5 2 sin


Pole voltage will have all odd harmonics

6. A single-phase full bridge inverter can operate in load

communication mode in case load consist of

a) RL

b) RLC under damped

c) RLC over damped

d) RLC critically damped

Answer: (b)

7. A dc chopper is fed from 100 V dc. Its load voltage consists of

rectangular pulses of duration in sec in an overall cycle time of 3

m sec. The average output voltage and ripple factor for this

chopper are respectively

a) 25 V, 1

b) 50 V, 1

c) 33.33 V, √2

3


d) 33.33 V, 1

Answer: (c)

Solution:

V0 = 1 × 100 = 33.33V
3

Rippled factor = � 1 − 1 = �11/3 − 1 = √3 − 1 = √2

8. Which of the following are the functions of feedback diodes in a

McMurray inverter?

1. To free-wheel the load current.

2. To provide required reverse bias across the outgoing

thyristor.

3. To provide the return path for the reactive current of load.

4. To provide a path for the excess of commutation current

above the load current.

Select the correct answer using the codes given below:

a) 2, 3 and 4

b) 2 and 4

c) 1, 2 and 3

d) 3 and 4

Answer: (a)

Solution:
Diode provide reverse bias voltage for thyristor and return path

for excess reactive power i.e. inductor current.

4


9. Which one of the following statements is correct?
For an SCR, dv/dt protection is achieved through at the use of
a) RL in series with SCR
b) RC across SCR
c) L in series with SCR
d) RC in series with SCR
Answer: (b)

10. When does a fully controlled line commutated converter
operate as an inverter?
a) In the range of firing angles 0 ≤ α ≤ 900
b) In the range of firing angles 900 ≤ α ≤ 1800
c) In the range of firing angles 900 ≤ α ≤ 1800 when there is a
suitable dc source in the load
d) When it supplies a back e.m.f load
Answer: (c)
Solution:
For 900 ≤ ≤ 1800 it operates as inverter. However, to supply
power to ac source, a dc source should be present in load

11. The advantages of SCR over SCS are
a) larger switching time and smaller VH
b) larger switching time and large VH
c) smaller switching time and smaller VH
d) smaller switching time and larger VH
Answer: (d)

5


12. A three-phase voltage source inverter with ideal devices

operating in 1800 conduction mode is feeding a balanced star-

connected resistive load. The DC voltage input is Vdc. The peak

of the fundamental component of the phase voltage is

a) Vdc
π

b) 2Vdc
π

c) 3Vdc
π

d) 4Vdc
π

Answer: (b)

Solution:

Peak value of fundamental component of phase voltage is

=6� 3 � 2
3


13. In a three phase half-wave rectifier, the peak inverse voltage

equals

a) √6E

b) √3E

c) 2E

d) �3/2E

where E is the R.M.S. voltage of secondary

Answer: (a)

6


14. In a current source inverter fed 3-phase induction motor, how

is air-gap flux maintained constant in the base speed region?

a) By measuring the air-gap flux.

b) By keeping v/f constant.

c) By varying the stator current as a function of slip frequency

using a function generator in the closed loop.

d) By varying the stator current as a function of stator frequency

using a function generator in the closed loop.

Answer: (b)

Solution:

Flux, ϕ ∝


By keep V/f constant, flux can be kept constant

15. Thermistor is used for measurement of power at

a) audio frequencies

b) high frequencies

c) very high frequencies

d) microwave frequencies

Answer: (d)

16. A bilateral p-n-p-n diode switch

a) consists of two p-n-p-n diodes in parallel but in opposite

order

b) is a 3-layer semiconductor device

c) is a unilateral device

d) is a bilateral device

Answer: (a)

7


17. A single-phase ac voltage controller feeds a pure resistive load.

At a firing angle α, thyristor conducts for an angle δ. If the load

is replaced by a pure inductance keeping the firing angle

constant, the conduction angle of the thyristor would be

a) 2δ

b) δ

c) δ/2

d) δ/3

Answer: (a)

Solution:

For firing angle, α ≤ ϕ (load angle), voltage controller will not

control the load voltage and current.

Here, α → constant

For inductor, ϕ =
So, 2

α >
2

For resistive load thyristor will conducts up to π i.e., when

voltage (Vs) goes to negative

δ = (π – α), α >
2

Thyristor will conduct after ‘π’ also as current in inductor

cannot change instantaneously.

8


18. A SCR's, break over voltages is 12 V and holding current IH =
5mA. What should be the input voltage V in the circuit for the
SCR to drop out if the voltage at drop out point is 0.7V?

a) 7.5 V
b) 11.3 V
c) 18.8 V
d) 8.2 V
Answer: (d)

9


19. In the single phase voltage controller circuit shown in the
figure, for what range of triggering angle (α), the output voltage
(V0) is not controllable?

a) 00 ˂ α ˂ 450
b) 450 ˂ α ˂ 1350
c) 900 ˂ α ˂ 1800
d) 1350 ˂ α ˂ 1800
Answer: (a)
Solution:
For controlling the load, the minimum value of firing angle α >
load phase angle

ϕ = tan−1 � �
= tan−1 �5500�
= 450

Firing angle for which output voltage is uncontrollable
=0

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